ΔABC∆ABC
ΔABC∆ABC
- AB2+AC2=2(AD2+BD2)AB2+AC2=2(AD2+BD2)
- AB2=AC2+BC2+2AB.BCAB2=AC2+BC2+2AB.BC
- AC2=AB2+BC2-2AB.BC
- AB2+BC2=2(AD2+BD2)
Answer: AB2+AC2=2(AD2+BD2)AB2+AC2=2(AD2+BD2)
Explanation:
Online Education and Job Solutions
ΔABC∆ABC
Answer: AB2+AC2=2(AD2+BD2)AB2+AC2=2(AD2+BD2)
Explanation:
Leave a Reply